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1827153250001 is a prime number
BaseRepresentation
bin11010100101101010110…
…100100000011011010001
320110200012110012011222122
4122211222310200123101
5214414002213000001
63515214351144025
7246002363241152
oct32455264403321
96420173164878
101827153250001
11644989415272
12256145b15015
131033b88c2041
1464612b03929
15327dd7b0b1b
hex1a96ad206d1

1827153250001 has 2 divisors, whose sum is σ = 1827153250002. Its totient is φ = 1827153250000.

The previous prime is 1827153249979. The next prime is 1827153250009. The reversal of 1827153250001 is 1000523517281.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1766613139600 + 60540110401 = 1329140^2 + 246049^2 .

It is an emirp because it is prime and its reverse (1000523517281) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1827153250001 - 214 = 1827153233617 is a prime.

It is not a weakly prime, because it can be changed into another prime (1827153250009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 913576625000 + 913576625001.

It is an arithmetic number, because the mean of its divisors is an integer number (913576625001).

Almost surely, 21827153250001 is an apocalyptic number.

It is an amenable number.

1827153250001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1827153250001 is an equidigital number, since it uses as much as digits as its factorization.

1827153250001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16800, while the sum is 35.

Adding to 1827153250001 its reverse (1000523517281), we get a palindrome (2827676767282).

The spelling of 1827153250001 in words is "one trillion, eight hundred twenty-seven billion, one hundred fifty-three million, two hundred fifty thousand, one".