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18282645092969 is a prime number
BaseRepresentation
bin1000010100000110000101…
…00100001111101001101001
32101201210200222020001121022
410022003002210033221221
54344020324120433334
6102514533050222225
73564606663122465
oct412030244175151
971653628201538
1018282645092969
115909698588a84
122073370a24975
13a2807a1a430a
14472c55a474a5
1521a890b3782e
hex10a0c290fa69

18282645092969 has 2 divisors, whose sum is σ = 18282645092970. Its totient is φ = 18282645092968.

The previous prime is 18282645092909. The next prime is 18282645092983. The reversal of 18282645092969 is 96929054628281.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 18282363020944 + 282072025 = 4275788^2 + 16795^2 .

It is a cyclic number.

It is not a de Polignac number, because 18282645092969 - 244 = 690459048553 is a prime.

It is a super-3 number, since 3×182826450929693 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (18282645092909) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9141322546484 + 9141322546485.

It is an arithmetic number, because the mean of its divisors is an integer number (9141322546485).

Almost surely, 218282645092969 is an apocalyptic number.

It is an amenable number.

18282645092969 is a deficient number, since it is larger than the sum of its proper divisors (1).

18282645092969 is an equidigital number, since it uses as much as digits as its factorization.

18282645092969 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 268738560, while the sum is 71.

The spelling of 18282645092969 in words is "eighteen trillion, two hundred eighty-two billion, six hundred forty-five million, ninety-two thousand, nine hundred sixty-nine".