Base | Representation |
---|---|
bin | 11010100111111010001… |
… | …011101100110110110001 |
3 | 20110220102002001010110002 |
4 | 122213322023230312301 |
5 | 214433413432101423 |
6 | 3520253151315345 |
7 | 246116110264421 |
oct | 32477213546661 |
9 | 6426362033402 |
10 | 1829558472113 |
11 | 645a03074239 |
12 | 2566b751bb55 |
13 | 1036accb88a8 |
14 | 647a0322481 |
15 | 328cea19228 |
hex | 1a9fa2ecdb1 |
1829558472113 has 2 divisors, whose sum is σ = 1829558472114. Its totient is φ = 1829558472112.
The previous prime is 1829558472109. The next prime is 1829558472199. The reversal of 1829558472113 is 3112748559281.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1378811395984 + 450747076129 = 1174228^2 + 671377^2 .
It is an emirp because it is prime and its reverse (3112748559281) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1829558472113 - 22 = 1829558472109 is a prime.
It is not a weakly prime, because it can be changed into another prime (1829558472103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 914779236056 + 914779236057.
It is an arithmetic number, because the mean of its divisors is an integer number (914779236057).
Almost surely, 21829558472113 is an apocalyptic number.
It is an amenable number.
1829558472113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1829558472113 is an equidigital number, since it uses as much as digits as its factorization.
1829558472113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4838400, while the sum is 56.
The spelling of 1829558472113 in words is "one trillion, eight hundred twenty-nine billion, five hundred fifty-eight million, four hundred seventy-two thousand, one hundred thirteen".
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