Base | Representation |
---|---|
bin | 10001101110010001… |
… | …011010001011111011 |
3 | 1211010020011102210012 |
4 | 101232101122023323 |
5 | 302433130123101 |
6 | 12424153212135 |
7 | 1242402464501 |
oct | 215621321373 |
9 | 54106142705 |
10 | 19029926651 |
11 | 808599660a |
12 | 383110104b |
13 | 1a43718238 |
14 | cc7528671 |
15 | 7659ebbbb |
hex | 46e45a2fb |
19029926651 has 2 divisors, whose sum is σ = 19029926652. Its totient is φ = 19029926650.
The previous prime is 19029926627. The next prime is 19029926659. The reversal of 19029926651 is 15662992091.
It is a strong prime.
It is an emirp because it is prime and its reverse (15662992091) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 19029926651 - 214 = 19029910267 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 19029926651.
It is not a weakly prime, because it can be changed into another prime (19029926659) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9514963325 + 9514963326.
It is an arithmetic number, because the mean of its divisors is an integer number (9514963326).
Almost surely, 219029926651 is an apocalyptic number.
19029926651 is a deficient number, since it is larger than the sum of its proper divisors (1).
19029926651 is an equidigital number, since it uses as much as digits as its factorization.
19029926651 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 524880, while the sum is 50.
Subtracting from 19029926651 its sum of digits (50), we obtain a square (19029926601 = 1379492).
The spelling of 19029926651 in words is "nineteen billion, twenty-nine million, nine hundred twenty-six thousand, six hundred fifty-one".
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