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191345107 is a prime number
BaseRepresentation
bin10110110011110…
…11000111010011
3111100001100010211
423121323013103
5342441020412
630553104551
74512256312
oct1331730723
9440040124
10191345107
1199011458
12540b8157
1330846a75
141b5ac279
1511be9ca7
hexb67b1d3

191345107 has 2 divisors, whose sum is σ = 191345108. Its totient is φ = 191345106.

The previous prime is 191345101. The next prime is 191345111. The reversal of 191345107 is 701543191.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 191345107 - 211 = 191343059 is a prime.

It is a super-2 number, since 2×1913451072 = 73225899945682898, which contains 22 as substring.

It is a Chen prime.

It is equal to p10625854 and since 191345107 and 10625854 have the same sum of digits, it is a Honaker prime.

It is not a weakly prime, because it can be changed into another prime (191345101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 95672553 + 95672554.

It is an arithmetic number, because the mean of its divisors is an integer number (95672554).

Almost surely, 2191345107 is an apocalyptic number.

191345107 is a deficient number, since it is larger than the sum of its proper divisors (1).

191345107 is an equidigital number, since it uses as much as digits as its factorization.

191345107 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3780, while the sum is 31.

The square root of 191345107 is about 13832.7548593908. The cubic root of 191345107 is about 576.2431648767.

Adding to 191345107 its reverse (701543191), we get a palindrome (892888298).

The spelling of 191345107 in words is "one hundred ninety-one million, three hundred forty-five thousand, one hundred seven".