Base | Representation |
---|---|
bin | 1000101100111100000101… |
… | …10001010010111100011011 |
3 | 2111202102001210020011202212 |
4 | 10112132002301102330123 |
5 | 10002012041423430121 |
6 | 104411025500345335 |
7 | 4013356455633542 |
oct | 426360261227433 |
9 | 74672053204685 |
10 | 19136273264411 |
11 | 6108714415716 |
12 | 21908a324524b |
13 | a8a7097853c4 |
14 | 4a22b4503159 |
15 | 232ba209825b |
hex | 116782c52f1b |
19136273264411 has 2 divisors, whose sum is σ = 19136273264412. Its totient is φ = 19136273264410.
The previous prime is 19136273264401. The next prime is 19136273264441. The reversal of 19136273264411 is 11446237263191.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 19136273264411 - 218 = 19136273002267 is a prime.
It is a super-2 number, since 2×191362732644112 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 19136273264411.
It is not a weakly prime, because it can be changed into another prime (19136273264401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9568136632205 + 9568136632206.
It is an arithmetic number, because the mean of its divisors is an integer number (9568136632206).
Almost surely, 219136273264411 is an apocalyptic number.
19136273264411 is a deficient number, since it is larger than the sum of its proper divisors (1).
19136273264411 is an equidigital number, since it uses as much as digits as its factorization.
19136273264411 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1306368, while the sum is 50.
The spelling of 19136273264411 in words is "nineteen trillion, one hundred thirty-six billion, two hundred seventy-three million, two hundred sixty-four thousand, four hundred eleven".
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