Base | Representation |
---|---|
bin | 1011001111101111011… |
… | …0000000000001100101 |
3 | 200110200201000212011120 |
4 | 2303323312000001211 |
5 | 11131140133014432 |
6 | 224431231524153 |
7 | 16646525121231 |
oct | 2637366000145 |
9 | 613621025146 |
10 | 193203798117 |
11 | 74a34564130 |
12 | 3153b689659 |
13 | 152b0300245 |
14 | 94cb6555c1 |
15 | 505b9b4c2c |
hex | 2cfbd80065 |
193203798117 has 24 divisors (see below), whose sum is σ = 298526927712. Its totient is φ = 110205369600.
The previous prime is 193203798103. The next prime is 193203798133. The reversal of 193203798117 is 711897302391.
It is not a de Polignac number, because 193203798117 - 216 = 193203732581 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (51).
It is a self number, because there is not a number n which added to its sum of digits gives 193203798117.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (193203798167) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 10119634 + ... + 10138707.
It is an arithmetic number, because the mean of its divisors is an integer number (12438621988).
Almost surely, 2193203798117 is an apocalyptic number.
193203798117 is a gapful number since it is divisible by the number (17) formed by its first and last digit.
It is an amenable number.
193203798117 is a deficient number, since it is larger than the sum of its proper divisors (105323129595).
193203798117 is a wasteful number, since it uses less digits than its factorization.
193203798117 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20258389 (or 20258372 counting only the distinct ones).
The product of its (nonzero) digits is 571536, while the sum is 51.
The spelling of 193203798117 in words is "one hundred ninety-three billion, two hundred three million, seven hundred ninety-eight thousand, one hundred seventeen".
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