Base | Representation |
---|---|
bin | 10010000101001110… |
… | …101110000100101011 |
3 | 1212010001221011001111 |
4 | 102011032232010223 |
5 | 304230231111033 |
6 | 12530312531151 |
7 | 1255060415134 |
oct | 220516560453 |
9 | 55101834044 |
10 | 19415097643 |
11 | 8263353247 |
12 | 391a0b0ab7 |
13 | 1aa5466c76 |
14 | d2274cc8b |
15 | 7897317cd |
hex | 4853ae12b |
19415097643 has 2 divisors, whose sum is σ = 19415097644. Its totient is φ = 19415097642.
The previous prime is 19415097631. The next prime is 19415097679. The reversal of 19415097643 is 34679051491.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 19415097643 - 233 = 10825163051 is a prime.
It is not a weakly prime, because it can be changed into another prime (19415037643) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9707548821 + 9707548822.
It is an arithmetic number, because the mean of its divisors is an integer number (9707548822).
Almost surely, 219415097643 is an apocalyptic number.
19415097643 is a deficient number, since it is larger than the sum of its proper divisors (1).
19415097643 is an equidigital number, since it uses as much as digits as its factorization.
19415097643 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 816480, while the sum is 49.
The spelling of 19415097643 in words is "nineteen billion, four hundred fifteen million, ninety-seven thousand, six hundred forty-three".
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