Base | Representation |
---|---|
bin | 101100010101100111110101… |
… | …101000111001011001100011 |
3 | 221120102210220111022212111022 |
4 | 230111213311220321121203 |
5 | 201024334324411010413 |
6 | 1530421422021240055 |
7 | 56034165040065446 |
oct | 5425476550713143 |
9 | 846383814285438 |
10 | 194999931344483 |
11 | 571510086739a1 |
12 | 19a5436256302b |
13 | 84a6550c0a065 |
14 | 36220930c965d |
15 | 17825e080a608 |
hex | b159f5a39663 |
194999931344483 has 2 divisors, whose sum is σ = 194999931344484. Its totient is φ = 194999931344482.
The previous prime is 194999931344437. The next prime is 194999931344503. The reversal of 194999931344483 is 384443139999491.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 194999931344483 - 218 = 194999931082339 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 194999931344398 and 194999931344407.
It is not a weakly prime, because it can be changed into another prime (194999931344783) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 97499965672241 + 97499965672242.
It is an arithmetic number, because the mean of its divisors is an integer number (97499965672242).
Almost surely, 2194999931344483 is an apocalyptic number.
194999931344483 is a deficient number, since it is larger than the sum of its proper divisors (1).
194999931344483 is an equidigital number, since it uses as much as digits as its factorization.
194999931344483 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3265173504, while the sum is 80.
The spelling of 194999931344483 in words is "one hundred ninety-four trillion, nine hundred ninety-nine billion, nine hundred thirty-one million, three hundred forty-four thousand, four hundred eighty-three".
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