Base | Representation |
---|---|
bin | 1011010110110110010… |
… | …1001101101000000000 |
3 | 200122121200122120001101 |
4 | 2311231211031220000 |
5 | 11144042133000000 |
6 | 225344435144144 |
7 | 20045025431101 |
oct | 2655545155000 |
9 | 618550576041 |
10 | 195112000000 |
11 | 75823701485 |
12 | 31992745054 |
13 | 15525746098 |
14 | 962cc563a8 |
15 | 511e292e6a |
hex | 2d6d94da00 |
195112000000 has 280 divisors, whose sum is σ = 504700180380. Its totient is φ = 75353600000.
The previous prime is 195111999977. The next prime is 195112000019. The reversal of 195112000000 is 211591.
The cubic root of 195112000000 is 5800.
It is a perfect power (a cube), and thus also a powerful number.
195112000000 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 14 ways, for example, as 195109490944 + 2509056 = 441712^2 + 1584^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 27 ways as a sum of consecutive naturals, for example, 6727999986 + ... + 6728000014.
Almost surely, 2195112000000 is an apocalyptic number.
195112000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 195112000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (252350090190).
195112000000 is an abundant number, since it is smaller than the sum of its proper divisors (309588180380).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
195112000000 is an frugal number, since it uses more digits than its factorization.
195112000000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 135 (or 36 counting only the distinct ones).
The product of its (nonzero) digits is 90, while the sum is 19.
Adding to 195112000000 its reverse (211591), we get a palindrome (195112211591).
The spelling of 195112000000 in words is "one hundred ninety-five billion, one hundred twelve million", and thus it is an aban number.
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