Base | Representation |
---|---|
bin | 10111010000100… |
… | …11000110110110 |
3 | 111121010210021011 |
4 | 23220103012312 |
5 | 344422112043 |
6 | 31205542434 |
7 | 4556302504 |
oct | 1350230666 |
9 | 447123234 |
10 | 195113398 |
11 | a0155647 |
12 | 55414a1a |
13 | 3156601c |
14 | 1bcad674 |
15 | 121e159d |
hex | ba131b6 |
195113398 has 4 divisors (see below), whose sum is σ = 292670100. Its totient is φ = 97556698.
The previous prime is 195113353. The next prime is 195113417. The reversal of 195113398 is 893311591.
195113398 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 893311591 = 4441 ⋅201151.
It is a self number, because there is not a number n which added to its sum of digits gives 195113398.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 48778348 + ... + 48778351.
It is an arithmetic number, because the mean of its divisors is an integer number (73167525).
Almost surely, 2195113398 is an apocalyptic number.
195113398 is a deficient number, since it is larger than the sum of its proper divisors (97556702).
195113398 is an equidigital number, since it uses as much as digits as its factorization.
195113398 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 97556701.
The product of its digits is 29160, while the sum is 40.
The square root of 195113398 is about 13968.2997533701. The cubic root of 195113398 is about 580.0013852523.
The spelling of 195113398 in words is "one hundred ninety-five million, one hundred thirteen thousand, three hundred ninety-eight".
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