Base | Representation |
---|---|
bin | 1011010111001000111… |
… | …1000101010000100011 |
3 | 200122211010120200001012 |
4 | 2311302033011100203 |
5 | 11144222130202033 |
6 | 225400304531135 |
7 | 20046664226111 |
oct | 2656217052043 |
9 | 618733520035 |
10 | 195190084643 |
11 | 75863794644 |
12 | 319b4920aab |
13 | 15538985708 |
14 | 9639380ab1 |
15 | 5126069248 |
hex | 2d723c5423 |
195190084643 has 2 divisors, whose sum is σ = 195190084644. Its totient is φ = 195190084642.
The previous prime is 195190084619. The next prime is 195190084673. The reversal of 195190084643 is 346480091591.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 195190084643 - 216 = 195190019107 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 195190084591 and 195190084600.
It is not a weakly prime, because it can be changed into another prime (195190084673) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 97595042321 + 97595042322.
It is an arithmetic number, because the mean of its divisors is an integer number (97595042322).
Almost surely, 2195190084643 is an apocalyptic number.
195190084643 is a deficient number, since it is larger than the sum of its proper divisors (1).
195190084643 is an equidigital number, since it uses as much as digits as its factorization.
195190084643 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 933120, while the sum is 50.
The spelling of 195190084643 in words is "one hundred ninety-five billion, one hundred ninety million, eighty-four thousand, six hundred forty-three".
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