Base | Representation |
---|---|
bin | 1011010111101110001… |
… | …0110110011111001011 |
3 | 200200020000110022001101 |
4 | 2311323202312133023 |
5 | 11200032120340323 |
6 | 225424004202231 |
7 | 20053601554426 |
oct | 2657342663713 |
9 | 620200408041 |
10 | 195346261963 |
11 | 75933965a06 |
12 | 31a39099377 |
13 | 15562138228 |
14 | 9651dd69bd |
15 | 5134b18dad |
hex | 2d7b8b67cb |
195346261963 has 2 divisors, whose sum is σ = 195346261964. Its totient is φ = 195346261962.
The previous prime is 195346261907. The next prime is 195346261967. The reversal of 195346261963 is 369162643591.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-195346261963 is a prime.
It is a super-3 number, since 3×1953462619633 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (195346261967) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 97673130981 + 97673130982.
It is an arithmetic number, because the mean of its divisors is an integer number (97673130982).
Almost surely, 2195346261963 is an apocalyptic number.
195346261963 is a deficient number, since it is larger than the sum of its proper divisors (1).
195346261963 is an equidigital number, since it uses as much as digits as its factorization.
195346261963 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6298560, while the sum is 55.
The spelling of 195346261963 in words is "one hundred ninety-five billion, three hundred forty-six million, two hundred sixty-one thousand, nine hundred sixty-three".
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