Base | Representation |
---|---|
bin | 10010001100110111… |
… | …000000111011010011 |
3 | 1212102222210101211201 |
4 | 102030313000323103 |
5 | 310011013214024 |
6 | 12551124252031 |
7 | 1261203422152 |
oct | 221467007323 |
9 | 55388711751 |
10 | 19543101139 |
11 | 8319631161 |
12 | 3954b41017 |
13 | 1ac5b33a93 |
14 | d3574d599 |
15 | 795ab8744 |
hex | 48cdc0ed3 |
19543101139 has 2 divisors, whose sum is σ = 19543101140. Its totient is φ = 19543101138.
The previous prime is 19543101023. The next prime is 19543101143. The reversal of 19543101139 is 93110134591.
It is a strong prime.
It is an emirp because it is prime and its reverse (93110134591) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 19543101139 - 211 = 19543099091 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 19543101098 and 19543101107.
It is not a weakly prime, because it can be changed into another prime (19543101169) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9771550569 + 9771550570.
It is an arithmetic number, because the mean of its divisors is an integer number (9771550570).
Almost surely, 219543101139 is an apocalyptic number.
19543101139 is a deficient number, since it is larger than the sum of its proper divisors (1).
19543101139 is an equidigital number, since it uses as much as digits as its factorization.
19543101139 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14580, while the sum is 37.
The spelling of 19543101139 in words is "nineteen billion, five hundred forty-three million, one hundred one thousand, one hundred thirty-nine".
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