Base | Representation |
---|---|
bin | 11100011100101111110… |
… | …101001111110101100011 |
3 | 20220220020012010111220121 |
4 | 130130233311033311203 |
5 | 224012331211413311 |
6 | 4054042001021111 |
7 | 261150014655610 |
oct | 34345765176543 |
9 | 6826205114817 |
10 | 1955012607331 |
11 | 694130716923 |
12 | 276a89924797 |
13 | 1124841487b4 |
14 | 6a8a1b83507 |
15 | 35cc372eb71 |
hex | 1c72fd4fd63 |
1955012607331 has 32 divisors (see below), whose sum is σ = 2356240803840. Its totient is φ = 1586547720576.
The previous prime is 1955012607323. The next prime is 1955012607367. The reversal of 1955012607331 is 1337062105591.
It is not a de Polignac number, because 1955012607331 - 23 = 1955012607323 is a prime.
It is a super-2 number, since 2×19550126073312 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1955012608331) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 20038390 + ... + 20135716.
It is an arithmetic number, because the mean of its divisors is an integer number (73632525120).
Almost surely, 21955012607331 is an apocalyptic number.
1955012607331 is a deficient number, since it is larger than the sum of its proper divisors (401228196509).
1955012607331 is a wasteful number, since it uses less digits than its factorization.
1955012607331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 99283.
The product of its (nonzero) digits is 170100, while the sum is 43.
The spelling of 1955012607331 in words is "one trillion, nine hundred fifty-five billion, twelve million, six hundred seven thousand, three hundred thirty-one".
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