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19612214803 is a prime number
BaseRepresentation
bin10010010000111110…
…101010011000010011
31212121210211201222001
4102100332222120103
5310131211333203
613002033454431
71263003034546
oct222076523023
955553751861
1019612214803
118354647295
123974111417
131b0725203c
14d409c085d
1579bbbb91d
hex490faa613

19612214803 has 2 divisors, whose sum is σ = 19612214804. Its totient is φ = 19612214802.

The previous prime is 19612214773. The next prime is 19612214813. The reversal of 19612214803 is 30841221691.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 19612214803 - 213 = 19612206611 is a prime.

It is not a weakly prime, because it can be changed into another prime (19612214813) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9806107401 + 9806107402.

It is an arithmetic number, because the mean of its divisors is an integer number (9806107402).

Almost surely, 219612214803 is an apocalyptic number.

19612214803 is a deficient number, since it is larger than the sum of its proper divisors (1).

19612214803 is an equidigital number, since it uses as much as digits as its factorization.

19612214803 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20736, while the sum is 37.

It can be divided in two parts, 196122 and 14803, that added together give a triangular number (210925 = T649).

The spelling of 19612214803 in words is "nineteen billion, six hundred twelve million, two hundred fourteen thousand, eight hundred three".