Base | Representation |
---|---|
bin | 1011011011010100011… |
… | …0110111110111100101 |
3 | 200202201022200011222101 |
4 | 2312311012313313211 |
5 | 11204021333143432 |
6 | 230103503332101 |
7 | 20116536343153 |
oct | 2666506676745 |
9 | 622638604871 |
10 | 196312006117 |
11 | 7628a011877 |
12 | 320685b1031 |
13 | 15687240286 |
14 | 97043883d3 |
15 | 518e7d04e7 |
hex | 2db51b7de5 |
196312006117 has 4 divisors (see below), whose sum is σ = 196314661120. Its totient is φ = 196309351116.
The previous prime is 196312006103. The next prime is 196312006127. The reversal of 196312006117 is 711600213691.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 196312006117 - 215 = 196311973349 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (196312006127) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1213317 + ... + 1365562.
It is an arithmetic number, because the mean of its divisors is an integer number (49078665280).
Almost surely, 2196312006117 is an apocalyptic number.
It is an amenable number.
196312006117 is a deficient number, since it is larger than the sum of its proper divisors (2655003).
196312006117 is an equidigital number, since it uses as much as digits as its factorization.
196312006117 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2655002.
The product of its (nonzero) digits is 13608, while the sum is 37.
The spelling of 196312006117 in words is "one hundred ninety-six billion, three hundred twelve million, six thousand, one hundred seventeen".
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