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196620915433 is a prime number
BaseRepresentation
bin1011011100011110000…
…1010001001011101001
3200210111211221101220011
42313013201101023221
511210134423243213
6230154300331521
720130310130335
oct2670741211351
9623454841804
10196620915433
1176428420a28
1232133b43ba1
131570623a357
1497333da7c5
1551ab99e03d
hex2dc78512e9

196620915433 has 2 divisors, whose sum is σ = 196620915434. Its totient is φ = 196620915432.

The previous prime is 196620915409. The next prime is 196620915493. The reversal of 196620915433 is 334519026691.

196620915433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 103408551184 + 93212364249 = 321572^2 + 305307^2 .

It is a cyclic number.

It is not a de Polignac number, because 196620915433 - 221 = 196618818281 is a prime.

It is a super-3 number, since 3×1966209154333 (a number of 35 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (196620915493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 98310457716 + 98310457717.

It is an arithmetic number, because the mean of its divisors is an integer number (98310457717).

Almost surely, 2196620915433 is an apocalyptic number.

It is an amenable number.

196620915433 is a deficient number, since it is larger than the sum of its proper divisors (1).

196620915433 is an equidigital number, since it uses as much as digits as its factorization.

196620915433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1049760, while the sum is 49.

The spelling of 196620915433 in words is "one hundred ninety-six billion, six hundred twenty million, nine hundred fifteen thousand, four hundred thirty-three".