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1975031113440 = 253571167797567
BaseRepresentation
bin11100101111011001000…
…001110010011011100000
320222210220022110222202210
4130233121001302123200
5224324330431112230
64111152231042120
7262456053320310
oct34573101623340
96883808428683
101975031113440
116a1673635850
1227a935b10340
13114324602898
146b8406c5440
1536595e03eb0
hex1cbd90726e0

1975031113440 has 384 divisors, whose sum is σ = 7872264142848. Its totient is φ = 404270254080.

The previous prime is 1975031113421. The next prime is 1975031113453. The reversal of 1975031113440 is 443111305791.

It is a super-2 number, since 2×19750311134402 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2077537 + ... + 2875103.

It is an arithmetic number, because the mean of its divisors is an integer number (20500687872).

Almost surely, 21975031113440 is an apocalyptic number.

1975031113440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1975031113440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (3936132071424).

1975031113440 is an abundant number, since it is smaller than the sum of its proper divisors (5897233029408).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1975031113440 is a wasteful number, since it uses less digits than its factorization.

1975031113440 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 797670 (or 797662 counting only the distinct ones).

The product of its (nonzero) digits is 45360, while the sum is 39.

The spelling of 1975031113440 in words is "one trillion, nine hundred seventy-five billion, thirty-one million, one hundred thirteen thousand, four hundred forty".