198113424737 has 2 divisors, whose sum is σ = 198113424738. Its totient is φ = 198113424736.

The previous prime is 198113424731. The next prime is 198113424779. The reversal of 198113424737 is 737424311891.

198113424737 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 198025890001 + 87534736 = 445001^2 + 9356^2 .

It is a cyclic number.

It is not a de Polignac number, because 198113424737 - 2²⁴ = 198096647521 is a prime.

It is a super-2 number, since 2×198113424737² (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (198113424731) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 99056712368 + 99056712369.

It is an arithmetic number, because the mean of its divisors is an integer number (99056712369).

Almost surely, 2^198113424737 is an apocalyptic number.

It is an amenable number.

198113424737 is a deficient number, since it is larger than the sum of its proper divisors (1).

198113424737 is an equidigital number, since it uses as much as digits as its factorization.

198113424737 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1016064, while the sum is 50.

The spelling of 198113424737 in words is "one hundred ninety-eight billion, one hundred thirteen million, four hundred twenty-four thousand, seven hundred thirty-seven".