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198124417 is a prime number
BaseRepresentation
bin10111100111100…
…10001110000001
3111210210202121101
423303302032001
5401204440132
631354254401
74624013131
oct1363621601
9453722541
10198124417
11a1921897
1256427401
133207b6aa
141c454ac1
15125d87e7
hexbcf2381

198124417 has 2 divisors, whose sum is σ = 198124418. Its totient is φ = 198124416.

The previous prime is 198124363. The next prime is 198124439. The reversal of 198124417 is 714421891.

198124417 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 158986881 + 39137536 = 12609^2 + 6256^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-198124417 is a prime.

It is a super-3 number, since 3×1981244173 (a number of 26 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (198124447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 99062208 + 99062209.

It is an arithmetic number, because the mean of its divisors is an integer number (99062209).

Almost surely, 2198124417 is an apocalyptic number.

It is an amenable number.

198124417 is a deficient number, since it is larger than the sum of its proper divisors (1).

198124417 is an equidigital number, since it uses as much as digits as its factorization.

198124417 is an evil number, because the sum of its binary digits is even.

The product of its digits is 16128, while the sum is 37.

The square root of 198124417 is about 14075.6675507771. The cubic root of 198124417 is about 582.9697238381.

The spelling of 198124417 in words is "one hundred ninety-eight million, one hundred twenty-four thousand, four hundred seventeen".