Base | Representation |
---|---|
bin | 10010011100111011… |
… | …111111000111110010 |
3 | 1220010210100112220000 |
4 | 102130323333013302 |
5 | 311034041334142 |
6 | 13034001530430 |
7 | 1300660234461 |
oct | 223473770762 |
9 | 56123315800 |
10 | 19812839922 |
11 | 8447916977 |
12 | 3a0b343a16 |
13 | 1b39997a25 |
14 | d5d4c69d8 |
15 | 7ae5eb14c |
hex | 49ceff1f2 |
19812839922 has 30 divisors (see below), whose sum is σ = 44399452383. Its totient is φ = 6603682788.
The previous prime is 19812839909. The next prime is 19812839947. The reversal of 19812839922 is 22993821891.
It can be written as a sum of positive squares in only one way, i.e., 9906419961 + 9906419961 = 99531^2 + 99531^2 .
It is an ABA number since it can be written as A⋅BA, here for A=2, B=99531.
It is a super-3 number, since 3×198128399223 (a number of 32 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (54).
It is an unprimeable number.
It is a polite number, since it can be written in 14 ways as a sum of consecutive naturals, for example, 1786029 + ... + 1797087.
Almost surely, 219812839922 is an apocalyptic number.
19812839922 is an abundant number, since it is smaller than the sum of its proper divisors (24586612461).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
19812839922 is an frugal number, since it uses more digits than its factorization.
19812839922 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22132 (or 11064 counting only the distinct ones).
The product of its digits is 1119744, while the sum is 54.
The spelling of 19812839922 in words is "nineteen billion, eight hundred twelve million, eight hundred thirty-nine thousand, nine hundred twenty-two".
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