Search a number
-
+
19813248000 = 21035537213
BaseRepresentation
bin10010011100111101…
…100010110000000000
31220010211010021200000
4102130331202300000
5311034142414000
613034014400000
71300663554300
oct223475426000
956124107600
1019813248000
118448075527
123a0b500000
131b39aab6b0
14d5d591600
157ae67c000
hex49cf62c00

19813248000 has 1584 divisors, whose sum is σ = 92757004704. Its totient is φ = 4180377600.

The previous prime is 19813247989. The next prime is 19813248019. The reversal of 19813248000 is 84231891.

It is a super-3 number, since 3×198132480003 (a number of 32 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (36).

It is an unprimeable number.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 1524095994 + ... + 1524096006.

Almost surely, 219813248000 is an apocalyptic number.

19813248000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 19813248000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (46378502352).

19813248000 is an abundant number, since it is smaller than the sum of its proper divisors (72943756704).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

19813248000 is an equidigital number, since it uses as much as digits as its factorization.

19813248000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 77 (or 30 counting only the distinct ones).

The product of its (nonzero) digits is 13824, while the sum is 36.

Adding to 19813248000 its reverse (84231891), we get a palindrome (19897479891).

The spelling of 19813248000 in words is "nineteen billion, eight hundred thirteen million, two hundred forty-eight thousand".