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198134436864 = 2103721319732
BaseRepresentation
bin1011100010000110111…
…0111001010000000000
3200221102022220020222110
42320201232321100000
511221234403434424
6231004404335320
720212645632300
oct2704156712000
9627368806873
10198134436864
11770347a6a91
12324969a4540
13158b7984c70
14983841d600
1552497b9c29
hex2e21bb9400

198134436864 has 792 divisors, whose sum is σ = 706066633440. Its totient is φ = 48826810368.

The previous prime is 198134436847. The next prime is 198134436887. The reversal of 198134436864 is 468634431891.

It is a super-3 number, since 3×1981344368643 (a number of 35 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (57).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 2714170332 + ... + 2714170404.

Almost surely, 2198134436864 is an apocalyptic number.

198134436864 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 198134436864, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (353033316720).

198134436864 is an abundant number, since it is smaller than the sum of its proper divisors (507932196576).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

198134436864 is a wasteful number, since it uses less digits than its factorization.

198134436864 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 215 (or 117 counting only the distinct ones).

The product of its digits is 11943936, while the sum is 57.

The spelling of 198134436864 in words is "one hundred ninety-eight billion, one hundred thirty-four million, four hundred thirty-six thousand, eight hundred sixty-four".