Base | Representation |
---|---|
bin | 100101110010… |
… | …1011011010111 |
3 | 1101021122211200 |
4 | 1023211123113 |
5 | 20033022403 |
6 | 1544403543 |
7 | 330263031 |
oct | 113453327 |
9 | 41248750 |
10 | 19814103 |
11 | 102036a1 |
12 | 67765b3 |
13 | 414992a |
14 | 28bac51 |
15 | 1b15ca3 |
hex | 12e56d7 |
19814103 has 12 divisors (see below), whose sum is σ = 29161080. Its totient is φ = 12959856.
The previous prime is 19814101. The next prime is 19814107. The reversal of 19814103 is 30141891.
It is not a de Polignac number, because 19814103 - 21 = 19814101 is a prime.
It is a super-3 number, since 3×198141033 (a number of 23 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (19814101) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 20293 + ... + 21246.
It is an arithmetic number, because the mean of its divisors is an integer number (2430090).
Almost surely, 219814103 is an apocalyptic number.
19814103 is a deficient number, since it is larger than the sum of its proper divisors (9346977).
19814103 is a wasteful number, since it uses less digits than its factorization.
19814103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 41598 (or 41595 counting only the distinct ones).
The product of its (nonzero) digits is 864, while the sum is 27.
The square root of 19814103 is about 4451.3035169487. The cubic root of 19814103 is about 270.5981389672.
Adding to 19814103 its reverse (30141891), we get a palindrome (49955994).
It can be divided in two parts, 1981 and 4103, that added together give a square (6084 = 782).
The spelling of 19814103 in words is "nineteen million, eight hundred fourteen thousand, one hundred three".
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