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19814103 = 325341539
BaseRepresentation
bin100101110010…
…1011011010111
31101021122211200
41023211123113
520033022403
61544403543
7330263031
oct113453327
941248750
1019814103
11102036a1
1267765b3
13414992a
1428bac51
151b15ca3
hex12e56d7

19814103 has 12 divisors (see below), whose sum is σ = 29161080. Its totient is φ = 12959856.

The previous prime is 19814101. The next prime is 19814107. The reversal of 19814103 is 30141891.

It is not a de Polignac number, because 19814103 - 21 = 19814101 is a prime.

It is a super-3 number, since 3×198141033 (a number of 23 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (19814101) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 20293 + ... + 21246.

It is an arithmetic number, because the mean of its divisors is an integer number (2430090).

Almost surely, 219814103 is an apocalyptic number.

19814103 is a deficient number, since it is larger than the sum of its proper divisors (9346977).

19814103 is a wasteful number, since it uses less digits than its factorization.

19814103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 41598 (or 41595 counting only the distinct ones).

The product of its (nonzero) digits is 864, while the sum is 27.

The square root of 19814103 is about 4451.3035169487. The cubic root of 19814103 is about 270.5981389672.

Adding to 19814103 its reverse (30141891), we get a palindrome (49955994).

It can be divided in two parts, 1981 and 4103, that added together give a square (6084 = 782).

The spelling of 19814103 in words is "nineteen million, eight hundred fourteen thousand, one hundred three".

Divisors: 1 3 9 53 159 477 41539 124617 373851 2201567 6604701 19814103