Base | Representation |
---|---|
bin | 10010011101001001… |
… | …001010101110101101 |
3 | 1220011000212002211111 |
4 | 102131021022232231 |
5 | 311040432422331 |
6 | 13034203552021 |
7 | 1301031505543 |
oct | 223511125655 |
9 | 56130762744 |
10 | 19816295341 |
11 | 8449866a97 |
12 | 3a1052b611 |
13 | 1b3a60775b |
14 | d5db45d93 |
15 | 7aea7edb1 |
hex | 49d24abad |
19816295341 has 8 divisors (see below), whose sum is σ = 20501333280. Its totient is φ = 19131371952.
The previous prime is 19816295333. The next prime is 19816295363. The reversal of 19816295341 is 14359261891.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 19816295341 - 23 = 19816295333 is a prime.
It is a super-2 number, since 2×198162953412 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (19816295371) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 471786 + ... + 512068.
It is an arithmetic number, because the mean of its divisors is an integer number (2562666660).
Almost surely, 219816295341 is an apocalyptic number.
It is an amenable number.
19816295341 is a deficient number, since it is larger than the sum of its proper divisors (685037939).
19816295341 is a wasteful number, since it uses less digits than its factorization.
19816295341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57275.
The product of its digits is 466560, while the sum is 49.
The spelling of 19816295341 in words is "nineteen billion, eight hundred sixteen million, two hundred ninety-five thousand, three hundred forty-one".
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