Base | Representation |
---|---|
bin | 1001000000101111011111… |
… | …01001010111011100010001 |
3 | 2121011110101020002021121222 |
4 | 10200113233221113130101 |
5 | 10044134102403004433 |
6 | 110051400220254425 |
7 | 4113465263000105 |
oct | 440275751273421 |
9 | 77143336067558 |
10 | 19816704734993 |
11 | 6350243225551 |
12 | 228073a3a1415 |
13 | b09926a5744a |
14 | 4c71c2959905 |
15 | 245728212b98 |
hex | 1205efa57711 |
19816704734993 has 2 divisors, whose sum is σ = 19816704734994. Its totient is φ = 19816704734992.
The previous prime is 19816704734987. The next prime is 19816704735029. The reversal of 19816704734993 is 39943740761891.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 15080888761744 + 4735815973249 = 3883412^2 + 2176193^2 .
It is a cyclic number.
It is not a de Polignac number, because 19816704734993 - 24 = 19816704734977 is a prime.
It is not a weakly prime, because it can be changed into another prime (19816704734933) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9908352367496 + 9908352367497.
It is an arithmetic number, because the mean of its divisors is an integer number (9908352367497).
Almost surely, 219816704734993 is an apocalyptic number.
It is an amenable number.
19816704734993 is a deficient number, since it is larger than the sum of its proper divisors (1).
19816704734993 is an equidigital number, since it uses as much as digits as its factorization.
19816704734993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 246903552, while the sum is 71.
The spelling of 19816704734993 in words is "nineteen trillion, eight hundred sixteen billion, seven hundred four million, seven hundred thirty-four thousand, nine hundred ninety-three".
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