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198180181801817 is a prime number
BaseRepresentation
bin101101000011111001101011…
…010101100111101101011001
3221222200211200121122010001122
4231003321223111213231121
5201433441003020124232
61541254415121455025
756513021440001135
oct5503715325475531
9858624617563048
10198180181801817
115816781a098086
121a288791aa1475
1386774072240b7
1436d1d871763c5
1517da1c472c312
hexb43e6b567b59

198180181801817 has 2 divisors, whose sum is σ = 198180181801818. Its totient is φ = 198180181801816.

The previous prime is 198180181801783. The next prime is 198180181801883. The reversal of 198180181801817 is 718108181081891.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 197163272922256 + 1016908879561 = 14041484^2 + 1008419^2 .

It is a cyclic number.

It is not a de Polignac number, because 198180181801817 - 230 = 198179108059993 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 198180181801817.

It is not a weakly prime, because it can be changed into another prime (198180181801117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 99090090900908 + 99090090900909.

It is an arithmetic number, because the mean of its divisors is an integer number (99090090900909).

Almost surely, 2198180181801817 is an apocalyptic number.

It is an amenable number.

198180181801817 is a deficient number, since it is larger than the sum of its proper divisors (1).

198180181801817 is an equidigital number, since it uses as much as digits as its factorization.

198180181801817 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2064384, while the sum is 62.

The spelling of 198180181801817 in words is "one hundred ninety-eight trillion, one hundred eighty billion, one hundred eighty-one million, eight hundred one thousand, eight hundred seventeen".