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1982472658073 is a prime number
BaseRepresentation
bin11100110110010100100…
…101000001110010011001
321000112002221001121220222
4130312110211001302121
5224440101000024243
64114422501125425
7263141343361565
oct34662445016231
97015087047828
101982472658073
116a4842150436
122802720b9875
13114c3c234a2b
146bd48b3c6a5
153687e38b168
hex1cd94941c99

1982472658073 has 2 divisors, whose sum is σ = 1982472658074. Its totient is φ = 1982472658072.

The previous prime is 1982472658069. The next prime is 1982472658081. The reversal of 1982472658073 is 3708562742891.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1367302246489 + 615170411584 = 1169317^2 + 784328^2 .

It is a cyclic number.

It is not a de Polignac number, because 1982472658073 - 22 = 1982472658069 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1982472657997 and 1982472658015.

It is not a weakly prime, because it can be changed into another prime (1982472658003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 991236329036 + 991236329037.

It is an arithmetic number, because the mean of its divisors is an integer number (991236329037).

It is a 1-persistent number, because it is pandigital, but 2⋅1982472658073 = 3964945316146 is not.

Almost surely, 21982472658073 is an apocalyptic number.

It is an amenable number.

1982472658073 is a deficient number, since it is larger than the sum of its proper divisors (1).

1982472658073 is an equidigital number, since it uses as much as digits as its factorization.

1982472658073 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 40642560, while the sum is 62.

The spelling of 1982472658073 in words is "one trillion, nine hundred eighty-two billion, four hundred seventy-two million, six hundred fifty-eight thousand, seventy-three".