Base | Representation |
---|---|
bin | 1011100010101101010… |
… | …0111010010011000001 |
3 | 200221211112202220120001 |
4 | 2320223110322103001 |
5 | 11222102110210234 |
6 | 231032354320001 |
7 | 20216642032423 |
oct | 2705324722301 |
9 | 627745686501 |
10 | 198295397569 |
11 | 77107645165 |
12 | 32520889001 |
13 | 15912120a99 |
14 | 985195c813 |
15 | 52589b1d14 |
hex | 2e2b53a4c1 |
198295397569 has 2 divisors, whose sum is σ = 198295397570. Its totient is φ = 198295397568.
The previous prime is 198295397563. The next prime is 198295397647. The reversal of 198295397569 is 965793592891.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 183601109169 + 14694288400 = 428487^2 + 121220^2 .
It is a cyclic number.
It is not a de Polignac number, because 198295397569 - 23 = 198295397561 is a prime.
It is a super-2 number, since 2×1982953975692 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (198295397561) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 99147698784 + 99147698785.
It is an arithmetic number, because the mean of its divisors is an integer number (99147698785).
Almost surely, 2198295397569 is an apocalyptic number.
It is an amenable number.
198295397569 is a deficient number, since it is larger than the sum of its proper divisors (1).
198295397569 is an equidigital number, since it uses as much as digits as its factorization.
198295397569 is an evil number, because the sum of its binary digits is even.
The product of its digits is 330674400, while the sum is 73.
The spelling of 198295397569 in words is "one hundred ninety-eight billion, two hundred ninety-five million, three hundred ninety-seven thousand, five hundred sixty-nine".
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