Base | Representation |
---|---|
bin | 1011100011011110000… |
… | …1111100101010010001 |
3 | 200222100211000222201111 |
4 | 2320313201330222101 |
5 | 11223012014013323 |
6 | 231104550533321 |
7 | 20225006236216 |
oct | 2706741745221 |
9 | 628324028644 |
10 | 198500141713 |
11 | 772021784a5 |
12 | 32579367241 |
13 | 15945679573 |
14 | 9870c17b0d |
15 | 526b956c0d |
hex | 2e3787ca91 |
198500141713 has 2 divisors, whose sum is σ = 198500141714. Its totient is φ = 198500141712.
The previous prime is 198500141669. The next prime is 198500141731. The reversal of 198500141713 is 317141005891.
Together with next prime (198500141731) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 165121947904 + 33378193809 = 406352^2 + 182697^2 .
It is a cyclic number.
It is not a de Polignac number, because 198500141713 - 213 = 198500133521 is a prime.
It is not a weakly prime, because it can be changed into another prime (198500141783) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 99250070856 + 99250070857.
It is an arithmetic number, because the mean of its divisors is an integer number (99250070857).
Almost surely, 2198500141713 is an apocalyptic number.
It is an amenable number.
198500141713 is a deficient number, since it is larger than the sum of its proper divisors (1).
198500141713 is an equidigital number, since it uses as much as digits as its factorization.
198500141713 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30240, while the sum is 40.
The spelling of 198500141713 in words is "one hundred ninety-eight billion, five hundred million, one hundred forty-one thousand, seven hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •