Base | Representation |
---|---|
bin | 10010100000100101… |
… | …101010100100011001 |
3 | 1220022001121202101201 |
4 | 102200211222210121 |
5 | 311200232104213 |
6 | 13044030514201 |
7 | 1302333020011 |
oct | 224045524431 |
9 | 56261552351 |
10 | 19874097433 |
11 | 8479456613 |
12 | 3a27965961 |
13 | 1b49595188 |
14 | d676b0c41 |
15 | 7b4b9b6dd |
hex | 4a096a919 |
19874097433 has 2 divisors, whose sum is σ = 19874097434. Its totient is φ = 19874097432.
The previous prime is 19874097409. The next prime is 19874097437. The reversal of 19874097433 is 33479047891.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 14570179849 + 5303917584 = 120707^2 + 72828^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-19874097433 is a prime.
It is not a weakly prime, because it can be changed into another prime (19874097437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9937048716 + 9937048717.
It is an arithmetic number, because the mean of its divisors is an integer number (9937048717).
Almost surely, 219874097433 is an apocalyptic number.
It is an amenable number.
19874097433 is a deficient number, since it is larger than the sum of its proper divisors (1).
19874097433 is an equidigital number, since it uses as much as digits as its factorization.
19874097433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4572288, while the sum is 55.
The spelling of 19874097433 in words is "nineteen billion, eight hundred seventy-four million, ninety-seven thousand, four hundred thirty-three".
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