Base | Representation |
---|---|
bin | 1011100100100100011… |
… | …1010100011100010101 |
3 | 201000010101011000120000 |
4 | 2321021013110130111 |
5 | 11224113024314000 |
6 | 231154130001513 |
7 | 20235220622034 |
oct | 2711107243425 |
9 | 630111130500 |
10 | 198795151125 |
11 | 7734375342a |
12 | 32640116299 |
13 | 1599181a94c |
14 | 989c08c71b |
15 | 52877cc000 |
hex | 2e491d4715 |
198795151125 has 160 divisors (see below), whose sum is σ = 375973678080. Its totient is φ = 104502182400.
The previous prime is 198795151117. The next prime is 198795151169. The reversal of 198795151125 is 521151597891.
198795151125 is a `hidden beast` number, since 1 + 9 + 8 + 7 + 9 + 515 + 112 + 5 = 666.
It is not a de Polignac number, because 198795151125 - 23 = 198795151117 is a prime.
It is a super-2 number, since 2×1987951511252 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 159 ways as a sum of consecutive naturals, for example, 273445512 + ... + 273446238.
It is an arithmetic number, because the mean of its divisors is an integer number (2349835488).
Almost surely, 2198795151125 is an apocalyptic number.
198795151125 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
198795151125 is a deficient number, since it is larger than the sum of its proper divisors (177178526955).
198795151125 is a wasteful number, since it uses less digits than its factorization.
198795151125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1106 (or 1087 counting only the distinct ones).
The product of its digits is 1134000, while the sum is 54.
The spelling of 198795151125 in words is "one hundred ninety-eight billion, seven hundred ninety-five million, one hundred fifty-one thousand, one hundred twenty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •