Base | Representation |
---|---|
bin | 10010100010010101… |
… | …011111110100100110 |
3 | 1220101002210011112112 |
4 | 102202111133310212 |
5 | 311230233213132 |
6 | 13050555121022 |
7 | 1303140136505 |
oct | 224225376446 |
9 | 56332704475 |
10 | 19903413542 |
11 | 8493a5a201 |
12 | 3a35743172 |
13 | 1b5268aa9c |
14 | d6b54283c |
15 | 7b753cab2 |
hex | 4a255fd26 |
19903413542 has 4 divisors (see below), whose sum is σ = 29855120316. Its totient is φ = 9951706770.
The previous prime is 19903413533. The next prime is 19903413547. The reversal of 19903413542 is 24531430991.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 24531430991 = 223 ⋅110006417.
It is a super-2 number, since 2×199034135422 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 19903413542.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (19903413547) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4975853384 + ... + 4975853387.
It is an arithmetic number, because the mean of its divisors is an integer number (7463780079).
Almost surely, 219903413542 is an apocalyptic number.
19903413542 is a deficient number, since it is larger than the sum of its proper divisors (9951706774).
19903413542 is an equidigital number, since it uses as much as digits as its factorization.
19903413542 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9951706773.
The product of its (nonzero) digits is 116640, while the sum is 41.
The spelling of 19903413542 in words is "nineteen billion, nine hundred three million, four hundred thirteen thousand, five hundred forty-two".
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