Base | Representation |
---|---|
bin | 1011100101111100110… |
… | …0100010010111110111 |
3 | 201001002012020200002121 |
4 | 2321133030202113313 |
5 | 11230342344231110 |
6 | 231255002220411 |
7 | 20250336550264 |
oct | 2713714422767 |
9 | 631065220077 |
10 | 199165617655 |
11 | 77513887414 |
12 | 327241b4707 |
13 | 15a204bb704 |
14 | 98d536626b |
15 | 52aa0a9cda |
hex | 2e5f3225f7 |
199165617655 has 4 divisors (see below), whose sum is σ = 238998741192. Its totient is φ = 159332494120.
The previous prime is 199165617601. The next prime is 199165617667. The reversal of 199165617655 is 556716561991.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 199165617655 - 213 = 199165609463 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 199165617593 and 199165617602.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19916561761 + ... + 19916561770.
It is an arithmetic number, because the mean of its divisors is an integer number (59749685298).
Almost surely, 2199165617655 is an apocalyptic number.
199165617655 is a deficient number, since it is larger than the sum of its proper divisors (39833123537).
199165617655 is an equidigital number, since it uses as much as digits as its factorization.
199165617655 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 39833123536.
The product of its digits is 15309000, while the sum is 61.
The spelling of 199165617655 in words is "one hundred ninety-nine billion, one hundred sixty-five million, six hundred seventeen thousand, six hundred fifty-five".
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