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19950443 is a prime number
BaseRepresentation
bin100110000011…
…0101101101011
31101112120212022
41030012231223
520101403233
61551335055
7331401362
oct114065553
941476768
1019950443
1110297077
12682148b
1341969c6
1429147d9
151b41398
hex1306b6b

19950443 has 2 divisors, whose sum is σ = 19950444. Its totient is φ = 19950442.

The previous prime is 19950433. The next prime is 19950451. The reversal of 19950443 is 34405991.

It is a strong prime.

It is an emirp because it is prime and its reverse (34405991) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 19950443 - 212 = 19946347 is a prime.

It is not a weakly prime, because it can be changed into another prime (19950433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9975221 + 9975222.

It is an arithmetic number, because the mean of its divisors is an integer number (9975222).

Almost surely, 219950443 is an apocalyptic number.

19950443 is a deficient number, since it is larger than the sum of its proper divisors (1).

19950443 is an equidigital number, since it uses as much as digits as its factorization.

19950443 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 19440, while the sum is 35.

The square root of 19950443 is about 4466.5918774833. The cubic root of 19950443 is about 271.2173789053.

The spelling of 19950443 in words is "nineteen million, nine hundred fifty thousand, four hundred forty-three".