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199514803 is a prime number
BaseRepresentation
bin10111110010001…
…01101010110011
3111220102101212011
423321011222303
5402033433203
631444143351
74641563545
oct1371055263
9456371764
10199514803
11a2691474
1256997b57
13324474c7
141c6d7695
15127b076d
hexbe45ab3

199514803 has 2 divisors, whose sum is σ = 199514804. Its totient is φ = 199514802.

The previous prime is 199514789. The next prime is 199514831. The reversal of 199514803 is 308415991.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 199514803 - 217 = 199383731 is a prime.

It is a super-2 number, since 2×1995148032 = 79612313232257618, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (199514863) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 99757401 + 99757402.

It is an arithmetic number, because the mean of its divisors is an integer number (99757402).

Almost surely, 2199514803 is an apocalyptic number.

199514803 is a deficient number, since it is larger than the sum of its proper divisors (1).

199514803 is an equidigital number, since it uses as much as digits as its factorization.

199514803 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 38880, while the sum is 40.

The square root of 199514803 is about 14124.9709026249. The cubic root of 199514803 is about 584.3302564921.

The spelling of 199514803 in words is "one hundred ninety-nine million, five hundred fourteen thousand, eight hundred three".