Base | Representation |
---|---|
bin | 100110000011… |
… | …1101001101011 |
3 | 1101112210010112 |
4 | 1030013221223 |
5 | 20102014113 |
6 | 1551404535 |
7 | 331415516 |
oct | 114075153 |
9 | 41483115 |
10 | 19954283 |
11 | 10299a48 |
12 | 682374b |
13 | 419868b |
14 | 2915d7d |
15 | 1b425a8 |
hex | 1307a6b |
19954283 has 2 divisors, whose sum is σ = 19954284. Its totient is φ = 19954282.
The previous prime is 19954241. The next prime is 19954289. The reversal of 19954283 is 38245991.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 19954283 - 28 = 19954027 is a prime.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 19954283.
It is not a weakly prime, because it can be changed into another prime (19954289) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9977141 + 9977142.
It is an arithmetic number, because the mean of its divisors is an integer number (9977142).
Almost surely, 219954283 is an apocalyptic number.
19954283 is a deficient number, since it is larger than the sum of its proper divisors (1).
19954283 is an equidigital number, since it uses as much as digits as its factorization.
19954283 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 77760, while the sum is 41.
The square root of 19954283 is about 4467.0217147446. The cubic root of 19954283 is about 271.2347788184.
The spelling of 19954283 in words is "nineteen million, nine hundred fifty-four thousand, two hundred eighty-three".
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