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19954393 is a prime number
BaseRepresentation
bin100110000011…
…1101011011001
31101112210021121
41030013223121
520102020033
61551405241
7331416034
oct114075331
941483247
1019954393
111029a038
126823821
134198744
14291601b
151b4262d
hex1307ad9

19954393 has 2 divisors, whose sum is σ = 19954394. Its totient is φ = 19954392.

The previous prime is 19954369. The next prime is 19954439. The reversal of 19954393 is 39345991.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 18636489 + 1317904 = 4317^2 + 1148^2 .

It is an emirp because it is prime and its reverse (39345991) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 19954393 - 221 = 17857241 is a prime.

It is a super-3 number, since 3×199543933 (a number of 23 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (19954093) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9977196 + 9977197.

It is an arithmetic number, because the mean of its divisors is an integer number (9977197).

Almost surely, 219954393 is an apocalyptic number.

It is an amenable number.

19954393 is a deficient number, since it is larger than the sum of its proper divisors (1).

19954393 is an equidigital number, since it uses as much as digits as its factorization.

19954393 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 131220, while the sum is 43.

The square root of 19954393 is about 4467.0340271818. The cubic root of 19954393 is about 271.2352772205.

The spelling of 19954393 in words is "nineteen million, nine hundred fifty-four thousand, three hundred ninety-three".