Base | Representation |
---|---|
bin | 1011100111011000001… |
… | …1001000101111000001 |
3 | 201002001220201000000101 |
4 | 2321312003020233001 |
5 | 11232134022414223 |
6 | 231401020122401 |
7 | 20263003522444 |
oct | 2716603105701 |
9 | 632056630011 |
10 | 199549029313 |
11 | 776a0252257 |
12 | 32810696401 |
13 | 15a81a7270a |
14 | 993024d65b |
15 | 52cda934ad |
hex | 2e760c8bc1 |
199549029313 has 2 divisors, whose sum is σ = 199549029314. Its totient is φ = 199549029312.
The previous prime is 199549029299. The next prime is 199549029371. The reversal of 199549029313 is 313920945991.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 188002022464 + 11547006849 = 433592^2 + 107457^2 .
It is a cyclic number.
It is not a de Polignac number, because 199549029313 - 233 = 190959094721 is a prime.
It is not a weakly prime, because it can be changed into another prime (199549029373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 99774514656 + 99774514657.
It is an arithmetic number, because the mean of its divisors is an integer number (99774514657).
Almost surely, 2199549029313 is an apocalyptic number.
It is an amenable number.
199549029313 is a deficient number, since it is larger than the sum of its proper divisors (1).
199549029313 is an equidigital number, since it uses as much as digits as its factorization.
199549029313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2361960, while the sum is 55.
The spelling of 199549029313 in words is "one hundred ninety-nine billion, five hundred forty-nine million, twenty-nine thousand, three hundred thirteen".
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