Base | Representation |
---|---|
bin | 11101000100011010111… |
… | …000111111110001100001 |
3 | 21001222011221102002212022 |
4 | 131010122320333301201 |
5 | 230212101400112122 |
6 | 4125404555111225 |
7 | 264215442562031 |
oct | 35043270776141 |
9 | 7058157362768 |
10 | 1997610941537 |
11 | 700200331902 |
12 | 283197a42515 |
13 | 1164b2609a03 |
14 | 6c98347b8c1 |
15 | 36e683b8642 |
hex | 1d11ae3fc61 |
1997610941537 has 2 divisors, whose sum is σ = 1997610941538. Its totient is φ = 1997610941536.
The previous prime is 1997610941509. The next prime is 1997610941657. The reversal of 1997610941537 is 7351490167991.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1668873838801 + 328737102736 = 1291849^2 + 573356^2 .
It is a cyclic number.
It is not a de Polignac number, because 1997610941537 - 210 = 1997610940513 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1997610941537.
It is not a weakly prime, because it can be changed into another prime (1997610946537) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 998805470768 + 998805470769.
It is an arithmetic number, because the mean of its divisors is an integer number (998805470769).
Almost surely, 21997610941537 is an apocalyptic number.
It is an amenable number.
1997610941537 is a deficient number, since it is larger than the sum of its proper divisors (1).
1997610941537 is an equidigital number, since it uses as much as digits as its factorization.
1997610941537 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12859560, while the sum is 62.
The spelling of 1997610941537 in words is "one trillion, nine hundred ninety-seven billion, six hundred ten million, nine hundred forty-one thousand, five hundred thirty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •