1998394675200 has 2808 divisors, whose sum is σ = 9483035234400. Its totient is φ = 412463923200.

The previous prime is 1998394675171. The next prime is 1998394675229. The reversal of 1998394675200 is 25764938991.

1998394675200 is a `hidden beast` number, since 1 + 9 + 98 + 39 + 467 + 52 + 0 + 0 = 666.

It is an interprime number because it is at equal distance from previous prime (1998394675171) and next prime (1998394675229).

It is a Harshad number since it is a multiple of its sum of digits (63).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 215 ways as a sum of consecutive naturals, for example, 13412044726 + ... + 13412044874.

It is an arithmetic number, because the mean of its divisors is an integer number (3377149300).

It is a 1-persistent number, because it is pandigital, but 2⋅1998394675200 = 3996789350400 is not.

Almost surely, 2^{1998394675200} is an apocalyptic number.

1998394675200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1998394675200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (4741517617200).

1998394675200 is an abundant number, since it is smaller than the sum of its proper divisors (7484640559200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1998394675200 is a wasteful number, since it uses less digits than its factorization.

1998394675200 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 223 (or 177 counting only the distinct ones).

The product of its (nonzero) digits is 29393280, while the sum is 63.

The spelling of 1998394675200 in words is "one trillion, nine hundred ninety-eight billion, three hundred ninety-four million, six hundred seventy-five thousand, two hundred".