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1998647113 is a prime number
BaseRepresentation
bin111011100100000…
…1110111101001001
312011021210210102011
41313020032331021
513043123201423
6530153535521
7100346135341
oct16710167511
95137723364
101998647113
11936203181
124794145a1
1325b0c2638
1414d625d21
15ba6e6b0d
hex7720ef49

1998647113 has 2 divisors, whose sum is σ = 1998647114. Its totient is φ = 1998647112.

The previous prime is 1998647087. The next prime is 1998647117. The reversal of 1998647113 is 3117468991.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1972514569 + 26132544 = 44413^2 + 5112^2 .

It is a cyclic number.

It is not a de Polignac number, because 1998647113 - 25 = 1998647081 is a prime.

It is not a weakly prime, because it can be changed into another prime (1998647117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 999323556 + 999323557.

It is an arithmetic number, because the mean of its divisors is an integer number (999323557).

Almost surely, 21998647113 is an apocalyptic number.

It is an amenable number.

1998647113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1998647113 is an equidigital number, since it uses as much as digits as its factorization.

1998647113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 326592, while the sum is 49.

The square root of 1998647113 is about 44706.2312547144. The cubic root of 1998647113 is about 1259.6368973460.

The spelling of 1998647113 in words is "one billion, nine hundred ninety-eight million, six hundred forty-seven thousand, one hundred thirteen".