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1998914963 is a prime number
BaseRepresentation
bin111011100100101…
…0000010110010011
312011022022101211112
41313021100112103
513043210234323
6530203403535
7100351332263
oct16711202623
95138271745
101998914963
11936376441
124795235ab
1325b187526
1414d6957a3
15ba74b178
hex77250593

1998914963 has 2 divisors, whose sum is σ = 1998914964. Its totient is φ = 1998914962.

The previous prime is 1998914947. The next prime is 1998914971. The reversal of 1998914963 is 3694198991.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1998914963 - 24 = 1998914947 is a prime.

It is a super-2 number, since 2×19989149632 = 7991322058610582738, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1998914933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 999457481 + 999457482.

It is an arithmetic number, because the mean of its divisors is an integer number (999457482).

Almost surely, 21998914963 is an apocalyptic number.

1998914963 is a deficient number, since it is larger than the sum of its proper divisors (1).

1998914963 is an equidigital number, since it uses as much as digits as its factorization.

1998914963 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3779136, while the sum is 59.

The square root of 1998914963 is about 44709.2268217647. The cubic root of 1998914963 is about 1259.6931651866.

The spelling of 1998914963 in words is "one billion, nine hundred ninety-eight million, nine hundred fourteen thousand, nine hundred sixty-three".