Base | Representation |
---|---|
bin | 11101000101111001101… |
… | …010111110110011001011 |
3 | 21002010021202120200101012 |
4 | 131011321222332303023 |
5 | 230223330440244201 |
6 | 4130230441514135 |
7 | 264303031664315 |
oct | 35057152766313 |
9 | 7063252520335 |
10 | 1999201103051 |
11 | 7009469a3779 |
12 | 2835604a294b |
13 | 1166a6ba9599 |
14 | 6ca947307b5 |
15 | 3700ccc25bb |
hex | 1d179abeccb |
1999201103051 has 2 divisors, whose sum is σ = 1999201103052. Its totient is φ = 1999201103050.
The previous prime is 1999201103017. The next prime is 1999201103089. The reversal of 1999201103051 is 1503011029991.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1999201103051 - 222 = 1999196908747 is a prime.
It is not a weakly prime, because it can be changed into another prime (1999201103651) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 999600551525 + 999600551526.
It is an arithmetic number, because the mean of its divisors is an integer number (999600551526).
Almost surely, 21999201103051 is an apocalyptic number.
1999201103051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1999201103051 is an equidigital number, since it uses as much as digits as its factorization.
1999201103051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21870, while the sum is 41.
The spelling of 1999201103051 in words is "one trillion, nine hundred ninety-nine billion, two hundred one million, one hundred three thousand, fifty-one".
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