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199965480000 = 26354111343271
BaseRepresentation
bin1011101000111011011…
…1110001010001000000
3201010010221022212221220
42322032313301101000
511234012130330000
6231510214115040
720306221351416
oct2721667612100
9633127285856
10199965480000
1177894333880
123290804ba80
1315b1a123a40
14996d6972b6
1553054061a0
hex2e8edf1440

199965480000 has 1120 divisors, whose sum is σ = 797711050752. Its totient is φ = 43545600000.

The previous prime is 199965479983. The next prime is 199965480017. The reversal of 199965480000 is 84569991.

It is an interprime number because it is at equal distance from previous prime (199965479983) and next prime (199965480017).

It is an unprimeable number.

It is a polite number, since it can be written in 159 ways as a sum of consecutive naturals, for example, 737879865 + ... + 737880135.

Almost surely, 2199965480000 is an apocalyptic number.

199965480000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 199965480000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (398855525376).

199965480000 is an abundant number, since it is smaller than the sum of its proper divisors (597745570752).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

199965480000 is a wasteful number, since it uses less digits than its factorization.

199965480000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 373 (or 348 counting only the distinct ones).

The product of its (nonzero) digits is 699840, while the sum is 51.

The spelling of 199965480000 in words is "one hundred ninety-nine billion, nine hundred sixty-five million, four hundred eighty thousand".