Base | Representation |
---|---|
bin | 10111110101110… |
… | …11011010111001 |
3 | 111221022220110111 |
4 | 23322323122321 |
5 | 402144401423 |
6 | 31502344321 |
7 | 4645642651 |
oct | 1372733271 |
9 | 457286414 |
10 | 199997113 |
11 | a2990878 |
12 | 56b8b0a1 |
13 | 32585bb4 |
14 | 1c7c1361 |
15 | 1285860d |
hex | bebb6b9 |
199997113 has 2 divisors, whose sum is σ = 199997114. Its totient is φ = 199997112.
The previous prime is 199997107. The next prime is 199997117. The reversal of 199997113 is 311799991.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 101848464 + 98148649 = 10092^2 + 9907^2 .
It is a cyclic number.
It is not a de Polignac number, because 199997113 - 25 = 199997081 is a prime.
It is not a weakly prime, because it can be changed into another prime (199997117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 99998556 + 99998557.
It is an arithmetic number, because the mean of its divisors is an integer number (99998557).
Almost surely, 2199997113 is an apocalyptic number.
It is an amenable number.
199997113 is a deficient number, since it is larger than the sum of its proper divisors (1).
199997113 is an equidigital number, since it uses as much as digits as its factorization.
199997113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 137781, while the sum is 49.
The square root of 199997113 is about 14142.0335524987. The cubic root of 199997113 is about 584.8007337493.
The spelling of 199997113 in words is "one hundred ninety-nine million, nine hundred ninety-seven thousand, one hundred thirteen".
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