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200000089433 is a prime number
BaseRepresentation
bin1011101001000011101…
…1110010110101011001
3201010020100110020011202
42322100323302311121
511234100010330213
6231513452003545
720310121465514
oct2722073626531
9633210406152
10200000089433
1177901922411
12329177605b5
1315b24350ab1
149974105d7b
155308490b58
hex2e90ef2d59

200000089433 has 2 divisors, whose sum is σ = 200000089434. Its totient is φ = 200000089432.

The previous prime is 200000089411. The next prime is 200000089463. The reversal of 200000089433 is 334980000002.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 195317150809 + 4682938624 = 441947^2 + 68432^2 .

It is a cyclic number.

It is not a de Polignac number, because 200000089433 - 222 = 199995895129 is a prime.

It is a super-2 number, since 2×2000000894332 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 200000089396 and 200000089405.

It is not a weakly prime, because it can be changed into another prime (200000089463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100000044716 + 100000044717.

It is an arithmetic number, because the mean of its divisors is an integer number (100000044717).

Almost surely, 2200000089433 is an apocalyptic number.

It is an amenable number.

200000089433 is a deficient number, since it is larger than the sum of its proper divisors (1).

200000089433 is an equidigital number, since it uses as much as digits as its factorization.

200000089433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 200000089433 its reverse (334980000002), we get a palindrome (534980089435).

The spelling of 200000089433 in words is "two hundred billion, eighty-nine thousand, four hundred thirty-three".