Base | Representation |
---|---|
bin | 101101011110100001110101… |
… | …101110101000110100001011 |
3 | 222020011202210122100112020011 |
4 | 231132201311232220310023 |
5 | 202203431001110401303 |
6 | 1545215155305412351 |
7 | 60062150361521542 |
oct | 5536416556506413 |
9 | 866152718315204 |
10 | 200010012200203 |
11 | 58802851700577 |
12 | 1a52334449a0b7 |
13 | 877ab2b65b4ba |
14 | 3756771641159 |
15 | 181cabd05c16d |
hex | b5e875ba8d0b |
200010012200203 has 2 divisors, whose sum is σ = 200010012200204. Its totient is φ = 200010012200202.
The previous prime is 200010012200171. The next prime is 200010012200233. The reversal of 200010012200203 is 302002210010002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200010012200203 - 25 = 200010012200171 is a prime.
It is not a weakly prime, because it can be changed into another prime (200010012200233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100005006100101 + 100005006100102.
It is an arithmetic number, because the mean of its divisors is an integer number (100005006100102).
Almost surely, 2200010012200203 is an apocalyptic number.
200010012200203 is a deficient number, since it is larger than the sum of its proper divisors (1).
200010012200203 is an equidigital number, since it uses as much as digits as its factorization.
200010012200203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 13.
Adding to 200010012200203 its reverse (302002210010002), we get a palindrome (502012222210205).
The spelling of 200010012200203 in words is "two hundred trillion, ten billion, twelve million, two hundred thousand, two hundred three".
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