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200010111013 = 383522219611
BaseRepresentation
bin1011101001000110001…
…0000001100000100101
3201010021001022101012101
42322101202001200211
511234110042023023
6231514450452101
720310302615116
oct2722142014045
9633231271171
10200010111013
1177907547809
123291ab94031
1315b2644c41b
14997559420d
1553092c01ad
hex2e91881825

200010111013 has 4 divisors (see below), whose sum is σ = 200532331008. Its totient is φ = 199487891020.

The previous prime is 200010110983. The next prime is 200010111053. The reversal of 200010111013 is 310111010002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 200010111013 - 229 = 199473240101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200010111053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 261109423 + ... + 261110188.

It is an arithmetic number, because the mean of its divisors is an integer number (50133082752).

Almost surely, 2200010111013 is an apocalyptic number.

It is an amenable number.

200010111013 is a deficient number, since it is larger than the sum of its proper divisors (522219995).

200010111013 is an equidigital number, since it uses as much as digits as its factorization.

200010111013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 522219994.

The product of its (nonzero) digits is 6, while the sum is 10.

Adding to 200010111013 its reverse (310111010002), we get a palindrome (510121121015).

The spelling of 200010111013 in words is "two hundred billion, ten million, one hundred eleven thousand, thirteen".

Divisors: 1 383 522219611 200010111013